Matlab code: Histogram equalization without using histeq function


              It is the re-distribution of gray level values uniformly. Let’s consider a 2 dimensional image which has values ranging between 0 and 255.




MATLAB CODE:

GIm=imread('tire.tif');
numofpixels=size(GIm,1)*size(GIm,2);
figure,imshow(GIm);
title('Original Image');


HIm=uint8(zeros(size(GIm,1),size(GIm,2)));
freq=zeros(256,1);
probf=zeros(256,1);
probc=zeros(256,1);
cum=zeros(256,1);
output=zeros(256,1);
%freq counts the occurrence of each pixel value.
%The probability of each occurrence is calculated by probf.
for i=1:size(GIm,1)
    for j=1:size(GIm,2)
        value=GIm(i,j);
        freq(value+1)=freq(value+1)+1;
        probf(value+1)=freq(value+1)/numofpixels;
    end
end
sum=0;
no_bins=255;
%The cumulative distribution probability is calculated. 
for i=1:size(probf)
   sum=sum+freq(i);
   cum(i)=sum;
   probc(i)=cum(i)/numofpixels;
   output(i)=round(probc(i)*no_bins);
end
for i=1:size(GIm,1)
    for j=1:size(GIm,2)
            HIm(i,j)=output(GIm(i,j)+1);
    end
end
figure,imshow(HIm);
title('Histogram equalization');



             




%The result is shown in the form of a table
figure('Position',get(0,'screensize'));
dat=cell(256,6);
for i=1:256
dat(i,:)={i,freq(i),probf(i),cum(i),probc(i),output(i)};   
end
   columnname =   {'Bin''Histogram''Probability''Cumulative histogram','CDF','Output'};
columnformat = {'numeric''numeric''numeric''numeric''numeric','numeric'};
columneditable =  [false false false false false false];
t = uitable('Units','normalized','Position',...
            [0.1 0.1 0.4 0.9], 'Data', dat,...
            'ColumnName', columnname,...
            'ColumnFormat', columnformat,...
            'ColumnEditable', columneditable,...
            'RowName',[]); 
    subplot(2,2,2); bar(GIm);
    title('Before Histogram equalization');
    subplot(2,2,4); bar(HIm);
    title('After Histogram equalization');




                              

Here is a simple Version of Histogram Equalization MATLAB CODE:

%Read a grayscale Image or a matrix mxn
A=imread('tire.tif');
figure,imshow(A);
%Specify the bin range[0 255]
bin=255;
%Find the histogram of the image.
Val=reshape(A,[],1);
Val=double(Val);
I=hist(Val,0:bin);
%Divide the result by number of pixels
Output=I/numel(A);
%Calculate the Cumlative sum
CSum=cumsum(Output);
%Perform the transformation S=T(R) where S and R in the range [ 0 1]
HIm=CSum(A+1);
%Convert the image into uint8
HIm=uint8(HIm*bin);
figure,imshow(HIm);



                          
                                 

36 comments:

  1. its nice that this space provides output too..and most importantly..the code works!!unlike most of the other sites!
    -thank u soo much for this code.

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  2. A graphical representation which shows a visual impression of the distribution of data termed as Histogram . Histograms consists of tabular frequencies which are shown as adjacent rectangles, with an area equal to the frequency of the observations in the interval.

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  3. @cool_images

    just change the original image to gray-scale value, because the error occur and mention that only 2D

    i had change in the end of the code as follows:

    GIm1=rgb2gray(GIm);
    subplot(2,2,2);
    bar(GIm1);

    title('Before Histogram equalization');
    subplot(2,2,4);
    bar(HIm);
    title('After Histogram equalization');

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  4. can i know, what is that mean with 1 and 2 in this code?
    numofpixels=size(GIm,1)*size(GIm,2);
    thanks.. ^^

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  5. @sumi

    it represents the dimensions. For a matrix, 1 represents rows and 2 represents columns.

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  6. This is very nice tutorial here. Can you provide me with the code for CLAHE.

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  7. Is there a bit problem with code, because max value of uint8 is 255, then
    freq(value+1)=freq(value+1)+1;
    cannot apply for the case value = 255. Further more, you set max gray value is 255, it is only right in almost case, not all case.

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  8. @socksau

    In matlab, the array range can start from 1. So the actual range 0 to 255 is mapped as 1 to 256.

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  9. can anybody give me code of face recognition system using k-means clustering algorithm and PCA .

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  10. After changing image to grayscale also, the last output is not working.. uitable is showing as unrecognised parameter : units.

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  11. @Aaron Angel 1 means rows and 2 means columns of the image

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  12. i really doint understand how the freq funtion works someone care to explain?

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  13. whether histogram functions can be applied to rgb image or only to gray scale???

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  14. nice, could you generalize median filter to any size of the window?

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  15. Love this blog. :) Good stuff! Keep it up!

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  16. CAN U GIVE ME CODE FOR COMPARING TWO IMAGES IN MATLAB I WANT TO DETECT FAULT IN FABRIC

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  17. Can you give me code for IMAGE FUSION using Improved Synthetic Variable Ratio method? Please sir...

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  18. freq=zeros(256,1);

    probf=zeros(256,1);

    probc=zeros(256,1);

    cum=zeros(256,1);

    output=zeros(256,1);
    what is the meaning of each line above??, please quick answer :) :)

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  19. @ahmed ali

    Pre-allocation of the vectors or 1D arrays. The gray level is[0 255] so there are 256 elements in total.

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  20. how to write a function to equilize a 100-by-100 image of normal random numbers with mean 128 and std-dev of 50.

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  21. can anybody provide full coding for image enhancement using histogram equalizatio..its urgent

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  22. histogram are also found different from that obtained from imhist(histeq(HIm))

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  23. how about GIm,3 and GIm,4?
    How do i get the rgb for the pic?

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  24. its amazing; help us with a similar code for bi-histogram equalization also

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  25. I think there is an error with code "freq(value+1)=freq(value+1)+1" for the case value=255; when value=255, freq(value+1),that is, freq(256) cannot count correctly. freq(256) always gets "0" regardless of how i and j vary, instead freq(255) counts correctly. You may check the workspace for value of freq and compare the values of freq with that from the function imhist in Matlab.

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  26. Can i get a matlab code for multi peak generalized histogram equalisation?

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  27. i need program for comparing two images in face detection

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  28. This code does NOT work. Yes, because the newest Matlab version RECOMMEND the use of HISTOGRAM instead of HIST (see: I=hist(Val,0:bin ). And, by using I = histogram (Val, 0:bin) you get the following error:

    Undefined operator '/' for input arguments of type 'matlab.graphics.chart.primitive.Histogram'.

    Error in histeq_test (line 15)
    Output = I/numel(A);

    By using I = histogram(Val,0:bin); and Output = double(I) /numel(A); The new error becomes:

    Index exceeds matrix dimensions.

    Error in histeq_test (line 21)
    HIm = CSum(A + 1);

    I therefore request the writer of this code to revise it, accordingly.

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  29. hello every one.... i need matlab code for adaptive contrast stretching without using of any built in matlab function.can any one help?

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  30. i like it its the simplest code i see it

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  31. thanks verey good code

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